Method: TGenerex And<TOtherGenerex, TOtherGenerexMatch>(GenerexNoResultBase<T, TOtherGenerex, TOtherGenerexMatch>)

• Declared in: RT.Generexes.GenerexBase<T, TMatch, TGenerex, TGenerexMatch>

Declaration

public TGenerex And<TOtherGenerex, TOtherGenerexMatch>(
    GenerexNoResultBase<T, TOtherGenerex, TOtherGenerexMatch> other
)

Summary

Returns a regular expression that only matches if the subarray matched by this regular expression also contains a match for the specified other regular expression.

Generic type parameters

TOtherGenerex Must derive from: RT.Generexes.GenerexNoResultBase<T, TOtherGenerex, TOtherGenerexMatch>.	The type of the other regular expression. (This is either Generex<T, TResult> or Stringerex<TResult>.)
TOtherGenerexMatch Must derive from: RT.Generexes.GenerexMatch<T>.	The type of the match object for the other regular expression. (This is either GenerexMatch<T, TResult> or StringerexMatch<TResult>.)

Parameters

GenerexNoResultBase<T, TOtherGenerex, TOtherGenerexMatch>

other

A regular expression which must match the subarray matched by this regular expression.

Remarks

It is important to note that a.And(b) is not the same as b.And(a). Consider the following input string:

foo {bar [baz]} quux

and the following regular expressions:

var curly = Stringerex.New('{').Then(Stringerex.Anything).Then('}');
var square = Stringerex.New('[').Then(Stringerex.Anything).Then(']');

Now consider:

• curly.And(square) means: match the curly brackets first (yielding the substring {bar [baz]}) and then match the square brackets inside of that. The result is a successful match, because the substring {bar [baz]} does contain [baz].
• square.And(curly) means: match the square brackets first (yielding the substring [baz]) and then match the curly brackets inside of that. The result is no match, because there are no curly brackets in [baz].